$Γ$-convergence for power-law functionals with variable exponents

created by prinari on 16 May 2020
modified on 18 Jan 2021

[BibTeX]

Published Paper

Inserted: 16 may 2020
Last Updated: 18 jan 2021

Journal: Nonlinear Analysis: RealWorld Applications
Year: 2020

ArXiv: 2005.06774 PDF

Abstract:

We study the $\Gamma$-convergence of the functionals $F_n(u):= | f(\cdot,u(\cdot),Du(\cdot))|_{p_n(\cdot)}$ and $\mathcal{F}_n(u):= \int_{\Omega} \frac{1}{p_n(x)} f^{p_n(x)}(x,u(x),Du(x))dx$ defined on $X\in \{L^1(\Omega,\mathbb{R}^d), L^\infty(\Omega,\mathbb{R}^d), C(\Omega,\mathbb{R}^d)\}$ (endowed with their usual norms) with effective domain the Sobolev space $W^{1,p_n(\cdot)}(\Omega, \mathbb{R}^d )$. Here $\Omega\subseteq \mathbb{R}^N$ is a bounded open set, $N,d \ge 1$ and the measurable functions $p_n: \overline{\Omega} \rightarrow (1, + \infty)$ satisfy the conditions ${\mathop{\rm ess\: sup }}_{\ \overline \Omega} p_n \le \, \beta \, {\mathop{\rm ess\: inf }}_{\ \overline \Omega} p_n$ for a fixed constant $\beta > 1$ and ${\mathop{\rm ess\: inf }}_{\ \overline \Omega} p_n \rightarrow + \infty$ as $n \rightarrow + \infty$. We show that when $f(x,u,\cdot)$ is level convex and lower semicontinuous and satisfies a uniform growth condition from below, then, as $n\to \infty$, the sequences $(F_n)_n$ $\Gamma$-converges in $X$ to the functional $F$ represented as $F(u)= | f(\cdot,u(\cdot),Du(\cdot))|_{\infty}$ on the effective domain $W^{1,\infty}(\Omega, \mathbb{R}^d )$. Moreover we show that the $\Gamma$-$\lim_n \mathcal F_n$ is given by the functional $\mathcal{F}(u):=\left\{\begin {array}{lll} \!\!\!\!\!\! & 0 & \hbox{if } | f(\cdot,u(\cdot),Du(\cdot)) |_{\infty}\leq 1,\\ \!\!\!\!\!\! & +\infty & \hbox{otherwise in } X.\\ \end{array}\right.$

Credits | Cookie policy | HTML 5 | CSS 2.1